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06.13.2008 at 08:03AM PDT, ID: 23482967
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9.1

Passing a variable value to query string using a hidden field

Asked by martyje in PHP for Windows

Tags:

I have a variable name $vars where I am saving all the variables such as:
if($publish_year) $vars .= "&year=".$publish_year;

and then passing it through a form as following:
<input id="vars" name="vars" value="<? echo $vars; ?>" type="hidden" />
<label for="perPage">Number</label>
          <select id="perPage" name="perPage">
            <option value="10"<? if($_GET['perPage'] == '10'){ ?> selected="selected"<? } ?>>10</option>
            <option value="25"<? if($_GET['perPage'] == '25'){ ?> selected="selected"<? } ?>>25</option>
            <option value="50"<? if($_GET['perPage'] == '50'){ ?> selected="selected"<? } ?>>50</option>  
            <option value="100"<? if($_GET['perPage'] == '100'){ ?> selected="selected"<? } ?>>100</option>
          </select>


The output in the query string shows all % % why is that?
here's the output

www.mytestwebsite.php?order_by=Date+DESC&vars=%26year%3D2000&perPage=25
Technicall I should have year=2000

any ideas?
thanks

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Zone: PHP for Windows
Tags: PHP
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Solution Provided By: Ray_Paseur
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Solution Grade: A
 
 
 
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